How to create and read a file in the same recipe

Chef Infra (archive)
1

I'm confused about the way Chef orders things. I'm trying to read a remote file and put the contents into a variable. So, I tried this:

remote_file "/tmp/tmpfile.txt" do
    source "https://domain.com/tmpfile.txt"
end

foo = File.read('/tmp/tmpfile.txt')

Which fails with "No such file or directory /tmp/tmpfile.txt".

But if I comment out the second part so it just reads

remote_file "/tmp/tmpfile.txt" do
    source "https://domain.com/tmpfile.txt"
end

then the /tmp/tmpfile.txt file is created as expected. I can then add back in the second part, and the recipe proceeds normally.

Why can't I have both lines in the same recipe, and what is the recommended way to deal with this?

2

Try putting the File.read in a ruby_block.

3

Thanks. Putting the code inside a ruby_block fixes that problem, but raises another. I'm trying to loop through the input file of IP addresses and create a firewalld rich rule for each address with the firewalld_rich_rule resource from the firewalld cookbook.

But when that resource is called within the ruby_block, it results in

    NoMethodError
    -------------
    undefined method `firewalld_rich_rule' for Chef::Resource::RubyBlock

I've tried calling the firewalld cookbook with include_recipe firewalld, without success.

Is there a way to load a resource inside ruby_block, or another approach to solving the original problem of the file getting created at the end of the run instead of at the beginning?

4

Well, one way you could do that is to put the recipe as part of a user-written resource, and turn on unified_mode. That way, the code in there (and anything that uses it) will execute in the order supplied, and you won't need the ruby_block.

5

Ohh thanks a lot for the guidance